In the Stable Matching Problem, it is stated that there can exist cases where the $m$ list of men can be content with their decisions, yet the list of $f$ cannot when the algorithm is run with men's proposals.
From what I read, an unstable match occurs when $m$ and $f$ prefer each other to their current partners.
I am a little lost in the definition of Stable Matching for this case. I'm going over the slides here.
Is a pair $(m, f)$ stable as long as the men are content even though the female's preferences have not been matched?