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I have started reading on algorithmic complexity for my thesis work. Already have studied on Polynomial time reducibility, NP-Complete, NP-Hard. Now trying to prove NP completeness of some of the classical problems. I have started with 3-SAT problem.

3-SAT problem — was shown to be NP-complete:

Input: A boolean Formula F in CNF where each clause contains at most three variables.

Question: Is that formula satisfiable?

Show now that the simple 3-SAT problem is also NP-complete:

Input: A boolean Formula F in CNF where each clause contains at most three variables and only clauses of length two may contain negated variables.

Question: Is that formula satisfiable?

Can any please explain the main idea? Thank you in advance.

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For general ideas and approaches, see here and here. –  Juho May 6 at 13:12
    
this is one of the most common/basic/earliest NP complete reductions found in many refs.... eg wikipedia. also there is some connection to the tseitin transform –  vzn May 6 at 15:12

1 Answer 1

up vote 4 down vote accepted

Main idea: For each variable $x_i$ introduce a new variable $y_i$ and add a new clause $(\lnot x_i, \lnot y_i)$. Replace each occurence of $\lnot x_i$ in the original clauses by $y_i$.

The new clauses ensure that $y_i$ can be set to true if and only if $x_i$ is false. Thus we neither add nor remove satisfying assignments for the original clauses, while the new clauses can always be satisfied.

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Thank you. Seems I have got some idea. Is there any way to reduce to graph problem? –  vessilli May 6 at 13:02
2  
Any NP-complete problem can be reduced to any other NP-complete problem. The question is just how complex the reduction function will get. –  FrankW May 6 at 13:05

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