I am looking to calculate the physical address corresponding to a logical address in a paging memory management scheme. I just want to make sure I am getting the calculation right, as I fear I could be wrong somewhere.
So, the data I have is as follows:
The logical address: 717
Logical memory size: 1024 bytes (4 pages)
Page Table (Page number - Frame number):
(0 - 5), (1 - 2), (2 - 7), (3 - 0)
Physical memory: 16 frames
So, with 1024 bytes in the logical memory, and 4 pages, then each page is 256 bytes.
Therefore, the size of the physical memory must be 4,096, right? (256*16).
Then, to calculate the logical address offset:
1024 mod 717 = 307
Is that how we calculate the offset?
And, we can assume that 717 is in page 2 (1024 / 717 = 2.8)?
So, according to the page table, the corresponding frame number is 3.
And so to get the physical address, we multiply the frame number and page size?
2 * 256 = 768
Then, do we add the offset, like so:
768 + 307 = 1,075
Thank you for taking the time to read. If I don't quite have this correct, would you be able to advise on the correct protocol to calculating this?