# Does $\mathsf{NSPACE}( f (n)) = \mathsf{coNSPACE}( f (n))$ hold for $f(n) < \log (n)$?

It's known that for $f(n) \geq \log n$, $\mathsf{NSPACE}(f(n)) = \mathsf{coNSPACE}(f(n))$.

What if $f(n)<\log n$? Are they also equal?

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AFAIR, the result only holds for space constructable bounds, not for arbitrary $f(n)\geq\log n$. –  Kaveh Feb 10 '13 at 6:58