Necessary properties of formal langagues in certain classes that rely on closure against repetition of certain subwords.

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Pumping lemma of regular language [duplicate]

I was wondering in how to solve this question, I feel a bit confused: for $\Sigma = \{1,\#\}$, consider $$D=\{w \mid w=x_1 \# x_2 \# \cdots \# x_k \text{ for } k \geq 0, \text{ each } x_i \in 1^*, ...
3
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1answer
132 views

How does a regular language satisfies the second condition of the pumping lemma

I'm a little bit confused about the second condition of the pumping lemma which are: $|y|\geq1$ $|xy|\leq p$ $\forall i \geq 0:xyiz\in L$ I don't understand why the length of ...
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0answers
11 views

An example of a context-free language [duplicate]

Is the following language produced by a CFG? $L=\{aw^{5} | w\in \{a,b\}^{*}\}$ I believe it's not, but I only sense this. I tried to find a suitable sequence of a's and b's to contradict the pumping ...
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1answer
38 views

Pumping Lemma confusion

I have the following language... $$A=\{a^ib^i | i>0\}\cup\{a^jb^k|j>2, k>3\}$$ Now, pumping lemma states that a regular language can be written in the form $x=pq^ir$. What confuses me is ...
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1answer
37 views

Pumping Lemma for Regular Language seems to Fail

Let $L = \{ab^ncd \mid n \geq 0\}$. If we take $p = 5$ and $w = abbcd$ and write $w_i = xy^iz$, where $x = abb$, $y=c$, $z=d$, then $w_2 = abbccd$ which is not in $L$. We conclude that ...
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1answer
61 views

How do I show that a^n w b^n is not regular?

$\ \sum= \{a,b\} $ Show that: $ L:= \{a^nwb^n: m,n \in \mathbb N, m\geqslant n, w\in\sum^m\} $ is not regular. I'm trying to proof this with the Pumping Lemma, but I'm kind of confused because of the ...
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1answer
90 views

Pumping Lemma Proof by contradiction [duplicate]

So, hi guys! I have a language which I am trying to prove that it is not regular using the Pumping Lemma. I am pretty new into the lemma so I would appreciate any help.The language is $$L = \{w | w ...
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2answers
53 views

L ={ $a^{m^n}$ | $m$>$n$ } is Regular or not by pumping Lemma [duplicate]

L ={ $a^{m^n}$ | $m$>$n$ } I am bit confuse whether to consider this language as L = $(a^{m})^{n}$ OR L = $a^{\left(m^n\right)}$. If it is considered as L = $(a^m)^{n}$ then want to check it ...
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0answers
103 views

Is the complement of this language Context-Free $\{(a^nb^n)^m \mid n>0,m>0\}$?

I've been asked to decide whether a given language is a Context-Free Language (CFL). If yes, I should find the grammar that creates her, and if not, I need to prove it (with the pumping lemma). The ...
2
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1answer
67 views

Help on using the pumping lemma?

I'm trying to prove that a language is not regular. That language is: {w ∈ {a, b}* | amount of a's in w is equivalent to the amount of b's in w, mod 2}. I have an inkling that this language is not ...
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1answer
59 views

Applying the context-free pumping lemma to a language with crossed nestings

For proving language $\{a^nb^mc^nd^m \mid n,m > 0\}$ is not context free. Do I have to use $z = a^pb^pc^pd^p$ as pumping lemma string where $p$ is pumping length? Or do I have to use a string that ...
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1answer
65 views

When using the Pumping lemma, how do I deal with different cases of y?

I want to prove L is not regular:$$L={\{www|w \in \Sigma^*\}}$$ $$\Sigma=\{a,b\}$$ I am sure I can do so using pumping lemma. I used $$ab^pab^pab^p$$as my chosen string but I am stuck. I do not know ...
2
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1answer
42 views

Pumping lemma for 0^n and n>0

When applying the pumping lemma to $L = \{ 0^n \mid n>0\}$ I do the following: $S = 0^p$ $x = \varepsilon$ $y = 0^p$ $z = \varepsilon$ so $S = xyz = (\varepsilon)0^p(\varepsilon)$ For $x y^i z$ ...
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2answers
105 views

Show that 0^i where i is a power of 2 is not context free

I'm having difficulty trying to use the pumping lemma in order to show that $L= \{0^i \mid \ i \text{ is a power of 2 }\} $ is not context free. I"m starting by stating that $ s = 0^p$ and then $ s = ...
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1answer
70 views

Pumping Lemma for $L=\{a^{2k} b^n b^k \mid k\ge0, n\ge0\}$

$L=\{a^{2k}b^nb^k\mid k\geq0, n\geq0\}$ over alphabet $\{a,b\}$ How do I prove that $L$ is not regular using Pumping Lemma? All the examples I've come across had same exponents all around, and I'm a ...
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2answers
95 views

High Level Explanation of the Pumping Lemma

I have a problem that I cannot figure out regarding using the pumping lemma to prove that a language is not regular. I don't understand how I go about proving through contradiction that the language ...
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1answer
54 views

How to prove that $\{0^n 1^{5n} \mid n \ge 10000 \}$ is not a regular language?

I proved that $$ \{ 0^n 1^{5n} \mid n \geq 0 \}$$ is not a regular language using Pumping Lemma by following way. Solve by contradiction that $ L = \{0^n 1^{5n} \mid n \geq 0 \}$ is regular ...
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2answers
92 views

Show that for any natural number n, there is a regular language that is not recognized by any DFA with at most n final states

Just as the question asks, I am trying to understand the relationship between the number of accept states a DFA has (not necessarily the total number of states) and the languages it can accept. I ...
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1answer
142 views

Why does this pumping lemma application “prove” that 0*1* is not regular?

Here is a proof that $0^*1^*$ is not regular, even though it is regular. I'm having a hard time figuring out what is wrong with the proof. Assume $0^*1^*$ is regular. Let $p$ be the pumping length as ...
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1answer
144 views

Can $\{a^mb^nc^n\mid m,n \ge 1\}$ be proved non-regular using the pumping lemma?

$\{a^mb^nc^n\mid m,n \ge 1\}$ intuitively seems like a non-regular language. It looks like the machine needs to remember the number of $b$s (which isn't limited). The pumping lemma can be used to ...
3
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1answer
131 views

Prove that the language is not regular without using Pumping Lemma

I am practising problems on Regular Languages and I came across this question: Prove that the language $$\{a^m b^n : m ≥ 0, n ≥ 0, m \ne n\}$$ is not regular. (Using the pumping lemma for this ...
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3answers
263 views

Clearing a Confusion regarding the Proof of equal no of a's and b's not being a regular language

I was wondering about its proof. The direct use of pumping lemma here is not a viability. So a certain teacher of mine proved this with the notion that $a^{n}b^{n}$ being a subset of this language ...
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3answers
114 views

Unable to understand an inequality in an application of the pumping lemma for context-free languages

The problem Prove that the language $\qquad L = \{a^n b^j \mid n = j^2\}$ is not context free using pumping lemma. Approach taken by the book To prove such statements, the book takes the ...
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1answer
53 views

CFL, pumping lemma

I have difficulty with proving that the language $ L = \{ a^p b^q | p \ge 1 , q \ge 1 , p \ge q^2 \vee q \ge p^2\}$ $ w = uvxyz $ I've chosen word $ w = a^{N^2} b^N $ where $ N $ is a constant ...
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0answers
47 views

Context-free Language, Pumping lemma

I want to prove that $ L = {a^n b^m c^{ \lfloor \frac{n}{m} \rfloor } } $ isn't context free language, so I choose N - constant from lemma so the word is $ w = a^N b^N c $ and $ w = uvxyz $ 1 ...
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1answer
118 views

requirement for pumping lemma in regular language

I am a bit confused on the theory of the pumping lemma. As I know is used to decide if a language is regular or not. This is what I have understood so far though For a regular language $L$, there ...
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2answers
257 views

Using the Pumping Lemma to show that the language $a^n b a^n$ is not regular

I've seen a lot couple of questions regarding the pumping lemma that are pretty similar to each other and this one is unfortunately not the exception. Most likely will be this question marked as a ...
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1answer
79 views

Is there a Context-free grammar for this language?

Is there a Context-free grammar for the following language: $L=\{ x\#1^m|x \in \{0,1\}^* \space and \space the \space m^{th} \space char \space in \space x \space ...
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1answer
72 views

Prove not context free

How can we prove that: $$ L = \{ w_1\#w_2 \mid w_1 \in w_2;\; |w_2| > |w_1|;\; w_1 , w_2 \in \{0, 1\}^*\} $$ is not context-free? The language defines $w_1$ as a sub-string of $w_2$, and they ...
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1answer
139 views

Is the language $L = \{a^nb^m : n = 2^m\}$ context-free?

Is the language $L = \{a^nb^m : n = 2^m\}$ context-free? Assume L is a context-free language. Then $\ \exists p\in \mathbb{Z}^{+}:\forall s\in L\left | s \right |\geq p. s = uvxyz,\left | vy \right ...
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1answer
53 views

Show L is not context free using the CFL pumping lemma

I am trying to use the pumping lemma to show this language is not context free: $L = a^nb^{n+1}c^{2n} : n \ge 0$ So I took $z = a^mb^{m+1}c^{2m}$ where $|z| = 4m+1 > m$. We can decompose $z = ...
3
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1answer
119 views

Show that the pumping lemmas for context-free and regular languages are equivalent for unary languages

I want to show that for any language $L \subseteq \{ a \}^* $, $L$ satisfies the pumping lemma for context free languages if and only if it satisfies the pumping lemma for regular languages. I know ...
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1answer
61 views

Pumping lemma not regular [duplicate]

How would about proving this is not regular with the pumping lemma. Please include all steps and explain all steps. I am really new with this. $1^{2x}0^y$ and $y>= x$ Does it matter which side ...
0
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1answer
105 views

Using the pumping lemma for a proof by contradiction [duplicate]

I'm trying to prove that the set of even-length strings with the two middle symbols being equal cannot be accepted by finite automata. I can explain why it cannot be accepted intuitively, but I'm ...
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1answer
88 views

Pumping lemma on {a^n | n=3^k} — help finishing the proof [duplicate]

I am working on a pumping lemma question and trying to prove that the following is not regular, but I can't finish the proof, if someone can help me it will be great. So I am given this language: $L ...
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0answers
48 views

Proving a language is regular or non-regular [duplicate]

I'm struggling a bit to understand two of the problems we were given in class. Could someone look over my work and maybe give me a few hints? State whether the following languages are regular or not ...
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4answers
991 views

Regular language not accepted by DFA having at most three states

Describe a regular language that cannot be accepted by any DFA that has only three states. I'm not really sure where to start on this and was wondering if someone could give me some tips or ...
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1answer
260 views

Prove that the language L = {a^(m+n) b^m a^n | m, n ≥ 0} ∪ {a^m b^n a^(m+n) | m, n ≥ 0} is not regular [duplicate]

In general, how can we go about proving that union of two languages as non regular. In this case, the individual languages can be proved as non regular using pumping lemma. How can we apply pumping ...
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0answers
24 views

Pumping Lemma Question [duplicate]

I have been trying to solve this question and am kinda stuck. Wondering on how to proceed and finish this proof. Prove that the language $ L = \{a^{2^n} | n >= 0\} $ is not regular. I have been ...
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3answers
79 views

How can both |y| = 0 and y⁰ = ε hold in the Pumping lemma?

There is something in the pumping lemma that I do not quite understand, namely if $s$ is at least of length $p$, then we could split it to $xyz$ such that the following conditions are met: For each ...
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1answer
93 views

Is this the correct way to use the pumping lemma?

I've been watching lectures from Coderisland on YouTube about finite state machines, DFAs and NFAs, and in one discussion he talks about how to use the pumping lemma to show how a language is not ...
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1answer
177 views

Proof that {$a^m b^n$ | m!=n} is not regular [duplicate]

I know that the language $\{a^m b^n | n\neq m\}$ satisfies the pumping lemma, but it's still not regular (I have to count the # of a's and b's). How can I formally prove it?
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1answer
62 views

Is the following language context-free? $L= \{a^nb^m| m\geq2^n\}$

Is $L=\{a^nb^m|m\geq2^n\}$ a context-free language?
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1answer
153 views

Pumping lemma for {w | w = ddd}

I want to use the pumping lemma to show that the following language is not context free: $$ L = \{w \in \{a,b\}^* \mid \exists d \in \{a,b\}^*, w=ddd \} $$ We suppose that $L$ is context-free. Then ...
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1answer
85 views

Uncertainty whether $\{a^i b^j c^k \mid i+j \le k\}$ is context-free or not

I'm having trouble with this particular language: $$\{a^i b^j c^k \mid i+j \le k\}$$ If it's not context-free, I don't know how to correctly apply the Pumping Lemma for CFLs; if it is context-free, I ...
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1answer
57 views

Pumping Lemma for regular language [duplicate]

I have a question to find out that L = {a^(2k)|k>=1} is regular. I know that it is regular set but I was looking to find out if pumping lemma is satisfying or not. So I tried it as - ...
2
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2answers
104 views

Is $\{w:w\in(a+b+c)^*, n_a(w) > n_b(w)>n_c(w)\}$ context-free?

So I've been given the following language on an assignment. It is the only question I have left of 10, and I've been racking my brains out trying to solve it for hours. $$L=\{w:w\in(a+b+c)^*, ...
0
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1answer
126 views

Context free language and the complement of it

Given the language $L_1 = \{a^i b^j c^k \mid i \neq j \vee i \neq k\}$, I need to determine whether it is context-free by using the pumping lemma. I must do the same for the complement of this ...
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1answer
59 views

Context-free Language: deciding z string

Let L = { x in {a,b}* | the number of a are less or equal the number of b^2} I know this is a NOT context free language. How can i choose the correct z=uvwxy and ...
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1answer
81 views

Using pumping lemma to prove a language is not context free

When using the pumping lemma for a context free language, if I write any $w \in L$ as $uvxyz$, is my goal to show that a string will not pump for ANY arrangement of $uvxyz$ that I choose, or is my ...