0
votes
1answer
80 views
-1
votes
0answers
41 views

Is given language regular? [duplicate]

Let $L$ be a regular language. Is $\frac{1}{2}L := \left\{ w: \exists_u |u|=|w| \wedge wu\in L \right\}$ regular too? I think the answer is YES. But I don't know how to prove it. I was trying to ...
3
votes
2answers
122 views

Prove that $L_1$ is regular if $L_2$, $L_1L_2$, $L_2L_1$ are regular

Prove that $L_1$ is regular if $L_2$, $L_1L_2$, $L_2L_1$ are regular. These are the things that I would use to start. As $L_1L_2$ is regular, then the homomorphism $h(L_1L_2)$ is regular. Let ...
6
votes
2answers
70 views

Regularity of the exact middle of words from a regular language

Let $L$ be a regular language. Is the language $L_2 = \{y : \exists x,z\ \ s.t.|x|=|z|\ and\ xyz \in L \}$ regular? I know it's very similar to the question here, but the catch is that it's not a ...
4
votes
4answers
128 views

Proof that regular languages are closed against taking the even-length subset

This question is on the GRE Computer Science test booklet (not homework). I tried applying closure properties of regular languages but no success. Suppose $L$ is a regular language over $\Sigma = ...
2
votes
2answers
64 views

Why is the subset of palindromes of a regular language context-free?

Why is $A(L) = \{x \in L \mid x = x^R \}$ context-free if $L$ is a regular language? Trying to understand the approach to determining whether a regular language is context-free.
3
votes
1answer
92 views

Can we say anything about the complement of a regular language?

Given a regular language $L$, can we say anything about its complement $\overline L$? One thing that is trivial to say is that the DFA's for both languages are equal in size as complementing the ...
1
vote
3answers
118 views

Are the non-regular languages closed under reverse, union, concatenation, etc?

My question: do the non-regular languages have closure properties? For example, if the reverse of L is non-regular, then L is non-regular ? thank you :-)
4
votes
5answers
243 views

Is $A$ regular if $A^{2}$ is regular?

If $A^2$ is regular, does it follow that $A$ is regular? My attempt on a proof: Yes, for contradiction assume that $A$ is not regular. Then $A^2 = A \cdot A$. Since concatenation of two ...
2
votes
1answer
88 views

Myhill-Nerode and closure properties

It is well known that regular languages are characterized by the Myhill-Nerode equivalence. For language $L$ over $\Sigma^*$ define the equivalence $x\sim_L y$ over $\Sigma^*$ iff for all ...
2
votes
2answers
124 views

Show that the language of strings not in the union of two regular languages is regular

Given languages $L_1,L_2$, defines $X(L_1,L_2)$ by $\qquad X(L_1,L_2) = \{w \mid w \not\in L_1 \cup L_2 \}$ If $L_1$ and $L_2$ are regular, how can we show that $X(L_1,L2)$ is also regular?
1
vote
1answer
82 views

Closure properties of languages

Let $P$ be a regular language and $Q$ be a context-free language such that $Q \subseteq P$(For example, let $P = a^*b^*$ and $Q = \{ a^nb^n | n \ge 0\}$). Then which of the following is always ...
2
votes
2answers
174 views

Is $\{a^nb^m \mid n,m\ge 0, n\ne m\}$ regular or not? [duplicate]

Possible Duplicate: Prove that the complement of $\{0^n1^n \mid n \geq{} 0\}$ is not regular using closure properties Is $L=\{ a^nb^m \mid n,m \ge 0, n\ne m\}$ a regular language? I ...
6
votes
3answers
184 views

Proving the language which consists of all strings in some language is the same length as some string in another language is regular

So I've been scratching my head over this problem for a couple of days now. Given some language $A$ and $B$ that is regular, show that the language $L$ which consists of all strings in $A$ whose ...
3
votes
1answer
130 views

If $L$ is a regular language, how to prove $L_1 = \{ uv \mid u \in L, |v| =2 \}$ is also regular?

If $L$ is a regular language, prove that the language $L_1 = \{ uv \mid u \in L, |v| =2 \}$ is also regular. My idea: $L$ can be represented as a DFA and then you could add 2 consecutive ...
8
votes
1answer
265 views

Prove that the complement of $\{0^n1^n \mid n \geq{} 0\}$ is not regular using closure properties

I want to prove that the complement of $\{0^n1^n \mid n \geq{} 0\}$ is not regular using closure properties. I understand pumping lemma can be used to prove that $\{0^n1^n \mid n \geq{} 0\}$ is not a ...
4
votes
1answer
371 views

Prove that regular languages are closed under the cycle operator

I've got in a few days an exam and have problems to solve this task. Let $L$ be a regular language over the alphabet $\Sigma$. We have the operation $\operatorname{cycle}(L) = \{ xy \mid x,y\in ...
8
votes
2answers
322 views

Closure against right quotient with a fixed language

I'd really love your help with the following: For any fixed $L_2$ I need to decide whether there is closure under the following operators: $A_r(L)=\{x \mid \exists y \in L_2 : xy \in L\}$ ...
5
votes
1answer
128 views

Closure against the operator $A(L)=\{ww^Rw \mid w \in L \wedge |w| \lt 2007\}$

I would like your help with the following question: Let $L$ be a language, and operator $A(L)=\{\,ww^Rw \mid w \in L\ \wedge\ |w| \lt 2007\,\}$ where $x^R$ is the reversed string of $x$. Which of ...
7
votes
1answer
378 views

How to prove regular languages are closed under left quotient?

L is a regular language over the alphabet $\sum = \{a,b\}$. The left quotient of L regarding $w \in \sum^*$ is the language $$w^{-1} L := \{v: wv \in L\}$$ How can I prove that $w^{-1}$ L is ...