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Timeline for Free and Bound in Lambda Calculus

Current License: CC BY-SA 3.0

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Mar 31, 2016 at 12:33 comment added Jay I think Slonneger didn't use a good example there, because $\lambda x.y$ may be easily misread as $\lambda xy$, which is usually short for $\lambda x.\lambda y$. I would give a different example: in $(\lambda x.\lambda y. xyx)x$, the last occurrence of $x$ is free, and the others are bound.
Mar 3, 2013 at 1:31 history tweeted twitter.com/#!/StackCompSci/status/308026889644163072
Mar 2, 2013 at 21:17 answer added user7081 timeline score: 11
Mar 2, 2013 at 21:12 history migrated from cstheory.stackexchange.com (revisions)
Mar 2, 2013 at 4:47 history asked user2054900 CC BY-SA 3.0