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Jan 24, 2019 at 12:49 comment added dkaeae @Euclid Problems do not have "corresponding languages". A decision problem is a language. Under the assumption mentioned in the answer, what you are saying is true: both a problem and its complement are valid problems (simply because they are both subsets of $\{0,1\}^\ast$). If they are promise problems, however, things are a bit different (but may be defined in equivalent fashion).
Jan 24, 2019 at 12:06 comment added user92484 I'm still scratching my head a bit. Can't we then say that every problems corresponding language is the complement of any other problems corresponding language (since were excluding the not valid instances)?
Jan 24, 2019 at 8:31 history answered dkaeae CC BY-SA 4.0