I try to use Bayes Theorem to calculate the probability of P(A/B)$P(A|B)$. I have P(A)$P(A)$ in column1, P(B/A)$P(B|A)$ in colmn2, P(B)$P(B)$ in column 3. I get the following:
my calculations were:
P(B/A) = 0,8A P(B) = (Bx0,55)+((1-Bx)(0,55)) P(A/B) = (AxBx)/Cx$$P(B/A) = 0.8\times A$$ $$P(B) = (Bx*0,55)+((1-Bx)*(0,55))$$ $$P(A/B) = (Ax*Bx)/Cx$$
The probability gets above 1. What am I doing wrong?
I try to use Bayes Theorem to calculate the probability of P(A/B). I have P(A) in column1, P(B/A) in colmn2, P(B) in column 3. I get the following:
my calculations were:
P(B/A) = 0,8A P(B) = (Bx0,55)+((1-Bx)(0,55)) P(A/B) = (AxBx)/Cx
The probability gets above 1. What am I doing wrong?
I try to use Bayes Theorem to calculate the probability of $P(A|B)$. I have $P(A)$ in column1, $P(B|A)$ in colmn2, $P(B)$ in column 3. I get the following:
my calculations were:
$$P(B/A) = 0.8\times A$$ $$P(B) = (Bx*0,55)+((1-Bx)*(0,55))$$ $$P(A/B) = (Ax*Bx)/Cx$$
The probability gets above 1. What am I doing wrong?
I try to use Bayes Theorem to calculate the probability of P(A/B). I have P(A) in column1, P(B/A) in colmn2, P(B) in column 3. I get the following:
my calculations were:
P(B/A) = 0,8A P(B) = (Bx0,55)+((1-Bx)(0,55)) P(A/B) = (AxBx)/Cx
The probability gets above 1. What am I doing wrong?
