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Sep 28, 2013 at 12:26 comment added Igor Shinkar @PratikDeoghare yes it does. because the function $f(i) = i^2$ is monotone.
Jul 13, 2013 at 6:30 comment added Pratik Deoghare I love this method but it doesn't give you $\Omega$ bound.
Jul 12, 2013 at 5:43 history answered ramgorur CC BY-SA 3.0