Timeline for If $L$ is regular then $L^{|2|}=\{w_1w_2 \mid w_1,w_2\in L, |w_1|=|w_2|\}$ is context-free
Current License: CC BY-SA 4.0
8 events
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Jan 14, 2021 at 9:27 | comment | added | Bader Abu Radi | You're welcome. | |
Jan 14, 2021 at 8:14 | vote | accept | Lightsong | ||
Jan 14, 2021 at 8:14 | comment | added | Lightsong | Thank you very much! I will be marking your answer as the solution since it's the most interesting one, although all of them were helpful. | |
Jan 13, 2021 at 19:50 | history | edited | Bader Abu Radi | CC BY-SA 4.0 |
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Jan 13, 2021 at 19:45 | history | edited | Bader Abu Radi | CC BY-SA 4.0 |
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Jan 13, 2021 at 19:34 | history | edited | Bader Abu Radi | CC BY-SA 4.0 |
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Jan 13, 2021 at 19:28 | history | edited | Bader Abu Radi | CC BY-SA 4.0 |
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Jan 13, 2021 at 19:21 | history | answered | Bader Abu Radi | CC BY-SA 4.0 |