Timeline for Floating point bitwise comparator. If f1 and f2 are floating point numbers with the following properties can we always say f1 > f2?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 11, 2021 at 22:53 | answer | added | gnasher729 | timeline score: 0 | |
| Mar 11, 2021 at 21:14 | vote | accept | VilePoison | ||
| Mar 11, 2021 at 21:10 | comment | added | plop | You haven't used that $b_{i,j}\in\{0,1\}$. The final difference that you got gets smaller if you put all $b_{1,j}$ possible (the non-negative summands) to be equal to $0$ and all $b_{2,j}$ possible (in the negative summands) equal to $1$. When you do that, you get $\sum_{k=1}^{23}(0-2^{e_2-k})$. | |
| Mar 11, 2021 at 21:05 | answer | added | orlp | timeline score: 0 | |
| Mar 11, 2021 at 20:42 | review | First posts | |||
| Mar 24, 2021 at 8:59 | |||||
| Mar 11, 2021 at 20:36 | history | asked | VilePoison | CC BY-SA 4.0 |