Imagine that an algorithm A runs in worst-case time $f(n)$ and that algorithm B runs in worst-case time $g(n)$. Answer either yes, no, or can’t tell and could you explain me why?

Is A more faster than B, for all $n>n_0$ if $g(h)=Ω(f(n)logn)$?

Is A more faster than B, for all $n>n_0$ if $g(n)=O(f(n)logn)$?

Is A more faster than B, for all $n>n_0$ if $g(n)=Θ(f(n)logn)$?

Imagine that an algorithm A runs in worst-case time $f(n)$ and that algorithm B runs in worst-case time $g(n)$. Answer either yes, no, or can’t tell and could you explain me why?

Is A more faster than B, for all $n>n_0$ if $g(h)=Ω(f(n)\log n)$?

Is A more faster than B, for all $n>n_0$ if $g(n)=O(f(n)\log n)$?

Is A more faster than B, for all $n>n_0$ if $g(n)=Θ(f(n)\log n)$?

Imagine that an algorithm A runs in worst-case time f(n) and that algorithm B runs in worst-case time g(n). Answer either yes, no, or can’t tell and could you explain me why?

Is A more faster than B, for all n>n0 if g(h)=Ω(f(n)logn)?

Is A more faster than B, for all n>n0 if g(n)=O(f(n)logn)?

Is A more faster than B, for all n>n0 if g(n)=Θ(f(n)logn)?

Imagine that an algorithm A runs in worst-case time $f(n)$ and that algorithm B runs in worst-case time $g(n)$. Answer either yes, no, or can’t tell and could you explain me why?

Is A more faster than B, for all $n>n_0$ if $g(h)=Ω(f(n)logn)$?

Is A more faster than B, for all $n>n_0$ if $g(n)=O(f(n)logn)$?

Is A more faster than B, for all $n>n_0$ if $g(n)=Θ(f(n)logn)$?