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May 22, 2021 at 4:05 vote accept ShyPerson
May 20, 2021 at 2:45 comment added ShyPerson @D.W. Many thanks again for all your help!
May 19, 2021 at 22:15 comment added D.W. Here's a construction that might get close to the right asymptotics: let $\Sigma=\{0,1\}^{\lg n}$; there's an isomorphism $\Sigma^{n/\lg n} \to \{0,1\}^n$; then consider the language of all words $w$ over $\Sigma^{n/\lg n}$ such that at least one $s \in \Sigma$ does not appear in $w$, i.e., $L=\{w \in \Sigma^{n/\lg n} \mid \exists s \in \Sigma . w \in (\Sigma \setminus \{s\})^{n/\lg n}\}$. Then by cs.stackexchange.com/q/3381/755, the minimal DFA for $L$ has at least $2^{n/\lg n}$ states. It's easy to see that $x \le n \cdot 2^n$ states.
May 19, 2021 at 21:21 answer added Yuval Filmus timeline score: 3
May 19, 2021 at 20:55 comment added D.W. That helped a ton! Thank you.
May 19, 2021 at 20:54 history reopened ShyPerson
D.W.
May 19, 2021 at 20:54 history edited D.W. CC BY-SA 4.0
Improve Latex and English wording.
May 19, 2021 at 20:49 comment added ShyPerson @D.W. Thanks for your ongoing help and patience with this question. I've substantially rewritten the question to make things more precise. To address your specific questions: "over" is formalized by set $A$. $A$ also addresses your first two questions. Your third question is addressed by set $S$. Your final question is addressed by $min(M)$ in the notation section. Please let me know what other improvements I can make so this question can be reopened. Many thanks
May 19, 2021 at 20:48 history edited ShyPerson CC BY-SA 4.0
Very substantial rewrite to address questions
May 12, 2021 at 3:27 review Reopen votes
May 19, 2021 at 21:04
May 12, 2021 at 3:15 history edited ShyPerson CC BY-SA 4.0
Correction: added "all" to specify the strings covered by the automaton
May 12, 2021 at 3:05 history edited ShyPerson CC BY-SA 4.0
Tried to address the objections.
May 12, 2021 at 1:54 history closed D.W. Needs details or clarity
May 12, 2021 at 1:27 history asked ShyPerson CC BY-SA 4.0