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Jan 6, 2023 at 13:46 vote accept nir shahar
Dec 7, 2021 at 15:43 answer added Tassle timeline score: 1
May 23, 2021 at 15:29 comment added Yuval Filmus The answer might be known for your parameters.
May 23, 2021 at 15:21 comment added nir shahar So, is this an open problem in the area of ECCs?
May 23, 2021 at 14:52 comment added Yuval Filmus If $|A_i| = pm$ then the condition on the intersection is equivalent to $|A_i \Delta A_j| \geq (4p-2)m$, and so you're interested in the size of constant-weight codes.
May 23, 2021 at 14:20 comment added nir shahar Just to note what I'm trying to achieve using this question: I'm trying to prove a lower bound on $dMA$ protocols for a certain problem, and solving this question would allow me to know if my thinking strategy could work in this case.
May 23, 2021 at 14:17 comment added nir shahar Yes I already managed to prove this (and something a bit stronger than this, in fact, but I didn't include it here since it would change the problem's definition). The actual problem I'm trying to solve is for $p=\frac{2}{3}$, and I want to see what the maximal $k$ is in this case. If the maximal $k$ is too large (when compared to $m$) for my usage case, then I would be interested in even lower values of $p$, and hence I asked this general question.
May 23, 2021 at 14:04 comment added Yuval Filmus If $p > 2/3$ then any two sets have intersection at least $(2p-1)m > m/3 > (1-p)m$, and so $k \leq 1$.
May 23, 2021 at 11:24 history edited nir shahar CC BY-SA 4.0
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May 23, 2021 at 10:27 history edited nir shahar CC BY-SA 4.0
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May 23, 2021 at 10:19 history asked nir shahar CC BY-SA 4.0