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S Feb 23, 2023 at 9:36 history suggested CommunityBot CC BY-SA 4.0
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S Feb 23, 2023 at 9:36
Dec 25, 2022 at 18:30 comment added Nino Rode OK, I'm late, but for anybody interested in the algorithms for computation of factorial, there is a very informative page from Lushny: luschny.de/math/factorial/FastFactorialFunctions.htm
Aug 13, 2021 at 2:25 comment added Matt Groff @magnetlion: $M(n \log{(n)})$, the time to multiply a number at least as large as $n \log{(n)}$, is almost certainly as large as $n \log{(n)}$, so we have $O(n \log{n} \log{ \log{ n}}) \in O(\log{ \log {n \underbrace{M(n \log{(n)}}_{\ge n \log{(n)})}}}))$.
Aug 12, 2021 at 23:52 comment added magnetlion The paper you linked says that its algorithm is of time O(log log n M (n log n)) where M(n) is the complexity of multiplication. Does that mean that if we consider multiplication to be one operation that the algorithm is O(log log n)? That seems awefully fast, especially if it requires we perform a prime number decomposition up to n.
Aug 12, 2021 at 23:46 vote accept magnetlion
Aug 12, 2021 at 6:25 history answered Bolton Bailey CC BY-SA 4.0