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Oct 29, 2021 at 14:07 vote accept J.Doe
Oct 29, 2021 at 14:06 comment added J.Doe aah I understand. thank a lot.
Oct 29, 2021 at 14:03 comment added Yuval Filmus I'm not sure how you would deduce $\Delta_2^P \neq \Sigma_2^P$; for all we know, it could be that P equals NP.
Oct 29, 2021 at 14:03 comment added Yuval Filmus Given an inclusion $A \subseteq B$, the opposite inclusion is $B \subseteq A$.
Oct 29, 2021 at 14:02 comment added J.Doe Thank you. I am unclear about the statement: "..opposite inclusion..". If I am correct it means that it cannot tell if the inclusion $\Delta_2^P \subseteq \Sigma_2^P$ is proper or not?
Oct 29, 2021 at 13:57 history answered Yuval Filmus CC BY-SA 4.0