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Oct 14, 2022 at 19:45 comment added Dan Doel The point here is that for elements to be 'of the form $σ:s$,' means not just that there is any old function of type $\mathcal{E} → Σ×\mathcal{E}$. The point is to characterize it in such a way that bisimilarity coincides with set theoretic equality. For examples like this, some amount of encoding is going to be necessary unless non-well-founded sets are allowed. But the point is to be considering sets of traces, not carrier sets of any algebra.
Oct 14, 2022 at 7:53 comment added N. Virgo Actually this doesn't make sense, does it? The unique map into the final coalgebra can be many-to-one, so the final one doesn't have to be the largest one at all. I think this idea of "largest set" might actually just be wrong.
Oct 14, 2022 at 5:56 history edited N. Virgo CC BY-SA 4.0
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Oct 14, 2022 at 5:32 history answered N. Virgo CC BY-SA 4.0