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Jul 5, 2023 at 15:40 comment added vidyarthi @InuyashaYagami From here, theorem 4.1 and its corollary, we have that the maximum number of edges for a graph with order $n$ and even girth $2k$ is less than $\frac{n+n^{1+\frac1{k}}}{2}$. Note, however that when we take the complete graph, which has girth $3$, this bound fails
Jul 5, 2023 at 13:49 comment added Inuyasha Yagami Could you please tell what is bound for even girth? It should be easily extended for odd girth.
Jul 5, 2023 at 10:21 history asked vidyarthi CC BY-SA 4.0