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Sep 29 at 1:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Feb 2 at 0:06 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 2 at 23:15 answer added gnasher729 timeline score: 0
Jan 1 at 18:44 comment added AspiringMat What do you mean by “solve approximately”? This is a decidability problem, how do you decide something approximately? Do you mean approximate the difference? In that case, you can binary search on the sqrt for each number ($2n$ in total) and calculate the difference to within any desired approximation (with the runtime of course depending on the approximation)
Jan 1 at 17:06 history asked Erel Segal-Halevi CC BY-SA 4.0