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Nov 19, 2013 at 9:06 comment added Sebastian $0^n 1^n$ is not a Kleene star operation since the number of 0s and 1s is coupled. Your grammar for this language is correct ($A$ could be eliminated though). The answer of bellpeace shows how to do the actual Kleene star and union
Nov 19, 2013 at 5:50 answer added zpavlinovic timeline score: 6
Nov 19, 2013 at 4:58 review First posts
Nov 19, 2013 at 11:23
Nov 19, 2013 at 4:39 history asked Taylor CC BY-SA 3.0