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Jan 3, 2014 at 14:05 comment added Raphael See here. Also, brushing up on fundamentals might help.
Jan 3, 2014 at 14:04 history edited Raphael
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Jan 3, 2014 at 13:03 history edited Juho CC BY-SA 3.0
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Jan 1, 2014 at 13:54 history edited David Richerby
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Dec 31, 2013 at 22:54 vote accept Yechiel Labunskiy
Dec 31, 2013 at 22:49 answer added ymbirtt timeline score: 11
Dec 31, 2013 at 22:44 review Close votes
Jan 3, 2014 at 14:28
Dec 31, 2013 at 22:40 comment added Yechiel Labunskiy L1 <= L2 if there exists a reduction function f such that for all input X, X is part of L1 IFF f(X) is part of L2.
Dec 31, 2013 at 22:37 comment added ymbirtt That's actually an interesting edge case that I hadn't spotted, but usually for these sorts of problems we ignore these edge cases $\emptyset$ and $\Sigma^*$. Can you recall the definition of a reduction?
Dec 31, 2013 at 22:24 review First posts
Jan 1, 2014 at 13:54
Dec 31, 2013 at 22:04 history asked Yechiel Labunskiy CC BY-SA 3.0