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Feb 21, 2014 at 12:42 history edited Ron Teller CC BY-SA 3.0
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Feb 21, 2014 at 12:38 comment added David Richerby The Dirac, Ore and Bondy–Chvátal theorems give some degree conditions for Hamiltonicity. As you observed in an earlier version of the question, the existence of a Hamiltonian cycle implies a matching (at least, for graphs of even order).
Feb 21, 2014 at 12:33 history edited David Richerby CC BY-SA 3.0
Shorter title.
Feb 21, 2014 at 12:32 history edited Ron Teller CC BY-SA 3.0
deleted 496 characters in body; edited title
Feb 21, 2014 at 0:41 comment added D.W. ... Perhaps you are asking for a threshold $t$ (depending only upon $n$) such that, if every vertex has degree $\ge t$, then the graph will surely have a perfect matching. Is that it? If so, what have you tried? Have you tried constructing counterexamples? Have you tried building small graphs by hand that lack perfect matchings and where all vertices have large-ish degree? We expect you to make an effort on your own before posting here, and to show us what you've tried.
Feb 19, 2014 at 19:36 history tweeted twitter.com/#!/StackCompSci/status/436222772092891136
Feb 19, 2014 at 9:14 history edited Ron Teller CC BY-SA 3.0
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Feb 19, 2014 at 8:31 answer added Suresh timeline score: 2
Feb 19, 2014 at 7:49 history asked Ron Teller CC BY-SA 3.0