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Jan 6, 2016 at 10:11 answer added Kaveh timeline score: 2
Jun 17, 2014 at 8:40 comment added Martin Berger @vzn Yes, I know that paper. It's another illustration of the difficulty my question is referring to.
Jun 17, 2014 at 1:31 comment added vzn your question reminded me of this paper. seems related. what do you think? The halting problem is decidable on a set of asymptotic probability one Hamkins/Miasnikov
Jun 12, 2014 at 17:18 comment added Martin Berger @NikosM. Thanks, but that link too doesn't say anything about the complexity of the underlying distribution. The reference talks about a transformation $\phi$ on the uniform distribution. But that transformation might be hard / or easy computationally.
Jun 12, 2014 at 17:11 comment added Nikos M. @MartinBerger, the stats.se link actually uses the theorem, the theorem is sth like the one stated here and here, this is basic probability results nothing more than that
Jun 12, 2014 at 10:06 comment added Martin Berger @NikosM. I'm not sure what that theorem is. The link you give doesn't appear to mention it.
Jun 12, 2014 at 8:11 comment added Nikos M. Is the probability simulation theorem of any help?
Jun 9, 2014 at 10:37 comment added Martin Berger @NicholasMancuso The examples I give are uniform distributions. But one can ask the same question about non-uniform distributions. One can also wonder about distributions on $\mathbb{R}$. As regards discrete distributions: prima facie, counting doesn't appear to be enough in general, you also need to be able to generate the $i$-th element, after you've uniformly chosen $i$. That said, it might be the case that counting is the core of the problem.
Jun 9, 2014 at 0:58 comment added vzn seems broad... there are many probabilistic complexity classes & then also the PCP thm is quite significant. eg have you heard of BPP? there are also strong connections to quantum computing... there is a strong argument to be made that probability theory breaks down on undecidable problems because its all about stats/computable math. also average case complexity? PAC learning?
Jun 8, 2014 at 21:49 comment added Martin Berger @NicholasMancuso I agree that counting + unform choice can always be used. So in some sense it gives an upper bound. Is this all that can be said? Where in the literature has this been investigated?
Jun 8, 2014 at 18:16 comment added Nicholas Mancuso Both of your examples are discrete uniform distributions. I would imagine the differing complexities would be in how hard it is to count $|\chi|$ where $\chi$ is the support.
Jun 8, 2014 at 9:18 history edited Martin Berger CC BY-SA 3.0
Clarified the question.
Jun 7, 2014 at 17:19 comment added Wandering Logic Another interesting example (but which is decidable) is the quantum fourier transform. Given $f(k)=a^k \mod b$ return a number $l \in [0,N]$ such that the probability of $l$ is proportional to $\left|F(l)\right|$, $F(l) = \sum_{k=0}^N f(k) e^{-2\pi ikl/N}$.
Jun 7, 2014 at 12:57 history tweeted twitter.com/#!/StackCompSci/status/475260188203548672
Jun 7, 2014 at 11:20 history edited Martin Berger CC BY-SA 3.0
edited body
Jun 7, 2014 at 10:50 history asked Martin Berger CC BY-SA 3.0