Timeline for Making a conjecture of a closed form
Current License: CC BY-SA 3.0
14 events
when toggle format | what | by | license | comment | |
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Aug 19, 2015 at 8:06 | vote | accept | user2989280 | ||
Dec 27, 2014 at 23:53 | history | tweeted | twitter.com/#!/StackCompSci/status/548990121572564992 | ||
Dec 8, 2014 at 17:50 | answer | added | Rick Decker | timeline score: 2 | |
Dec 8, 2014 at 3:13 | history | edited | user2989280 | CC BY-SA 3.0 |
edited body
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S Dec 7, 2014 at 9:10 | history | suggested | Jonathan Prieto-Cubides | CC BY-SA 3.0 |
it's more accurate use \mod that % in latex
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Dec 7, 2014 at 4:57 | comment | added | Jonathan Prieto-Cubides | The worst case for the euclidean algorithm could find out started with (1,1) and iterate reversing euclidean algorithm always in each step put de minimum quotation $q = 1$, and there appears Fibonacci numbers in the residues. | |
Dec 7, 2014 at 4:53 | review | Suggested edits | |||
S Dec 7, 2014 at 9:10 | |||||
Dec 7, 2014 at 4:27 | history | reopened |
Rick Decker Yuval Filmus David Richerby A.Schulz Ran G. |
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Dec 2, 2014 at 1:48 | review | Reopen votes | |||
Dec 7, 2014 at 4:27 | |||||
Dec 2, 2014 at 1:42 | comment | added | Yuval Filmus | You can start by following the advice. What is $T(F(n),F(n+1))$ equal to according to the formula? | |
Dec 1, 2014 at 22:57 | history | edited | Raphael |
edited tags
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Dec 1, 2014 at 22:57 | history | closed | Raphael | Duplicate of Solving or approximating recurrence relations for sequences of numbers | |
Dec 1, 2014 at 21:38 | review | First posts | |||
Dec 1, 2014 at 22:58 | |||||
Dec 1, 2014 at 21:38 | history | asked | user2989280 | CC BY-SA 3.0 |