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Raphael
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I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

Thanks in advance for your answers.

I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

Thanks in advance for your answers.

I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

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David Richerby
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I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

Thanks in advance for your answers PeterMcCoy.

I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

Thanks in advance for your answers PeterMcCoy

I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

Thanks in advance for your answers.

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PeterMcCoy
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Omega-Language to Büchi automaton

I'm currently preparing a presentation about LTL and a book says that the language $L = (a(a \cup b))^\omega$ cannot be described by any LTL (or FO) formula which is understandable but how does the corresponding Büchi automaton $\mathcal{A}$ look like with $L(\mathcal{A}) = L$?

Thanks in advance for your answers PeterMcCoy