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Apr 30, 2015 at 13:03 history edited babou CC BY-SA 3.0
Shorter title to make it more general (with ok from OP)
Apr 28, 2015 at 1:13 comment added Will Ness just for completeness, in ND-supporting language, we can write code following the ND "thinking", e.g. mapM (const [0,1]) [0..2] (in Haskell, using list monad to model non-determinism by exhaustive calculation) which returns [[0,0,0],[0,0,1],[0,1,0],[0,1,1],[1,0,0],[1,0,1],[1,1,0],[1,1,1]]. -- -- -- and powerset is, similarly, filterM (const [True,False]) [0..2] which returns [[0,1,2],[0,1],[0,2],[0],[1,2],[1],[2],[]].
Apr 22, 2015 at 11:26 comment added babou Thanks. - ** Is it ok for me to shorten the title? ** - - - - - Also, I added at the beginning a section explaining better the generality of underlying principles.
Apr 22, 2015 at 10:09 vote accept ManMohan Vyas
Apr 21, 2015 at 15:11 history tweeted twitter.com/#!/StackCompSci/status/590533289309577218
Apr 21, 2015 at 8:17 comment added babou @YuvalFilmus Thank you. Actually I know C arrays are from 0 to n-1, but I am language agnostic. The point is the array is missing one element. Whether it is A[0] or A[n] is immaterial to me. But you are right ... and doing that may disturb readers.
Apr 21, 2015 at 5:24 answer added Yuval Filmus timeline score: 3
Apr 21, 2015 at 5:15 comment added Yuval Filmus @babou C arrays are zero based.
Apr 20, 2015 at 16:41 comment added babou Maybe you title should better be "How does one formulate a backtracking algorithm?", since that is really your question. Generating permutations is only an example of a problem that can use that skill. I think mentioning the example in the title is misleading regarding the topic ... You can edit it.
Apr 20, 2015 at 16:37 answer added babou timeline score: 6
Apr 20, 2015 at 15:53 comment added babou There seems to be a bug in your program: A[n] never gets a value.
Apr 20, 2015 at 15:38 history edited babou CC BY-SA 3.0
tags titke syntax
Apr 20, 2015 at 15:27 review First posts
Apr 20, 2015 at 15:39
Apr 20, 2015 at 15:22 history asked ManMohan Vyas CC BY-SA 3.0