Timeline for Complexity of an algorithm
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 3, 2015 at 4:43 | comment | added | André Souza Lemos | Wolphram Alpha gives us $\frac{n^7}{21}+\frac{n^6}{6}+\frac{4 n^5}{15}+\frac{n^4}{4}+\frac{n^3}{6}+\frac{n^2}{12}+\frac{2n}{105}$ | |
| May 3, 2015 at 0:35 | history | answered | Yuval Filmus | CC BY-SA 3.0 |