Timeline for Context-free Grammar To Generate $L=\{a^nb^k | 1 =< n =< 2k }
Current License: CC BY-SA 3.0
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| when toggle format | what | by | license | comment | |
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| Nov 5, 2015 at 21:34 | comment | added | Rick Decker | Right track, but you're interpreting things backwards. For example, starting with two $a$'s, you could follow with 1 or more $b$'s, not 4 or more. | |
| Nov 5, 2015 at 21:26 | history | answered | TLW | CC BY-SA 3.0 |