Timeline for Rice's Theorem: implication of having an undecidable property
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Feb 1, 2016 at 15:34 | comment | added | Divyanshu Shende | David - <O> is the encoding of a O, for any object O. It is simply one of the possible representations of O in the form of a string. | |
Feb 1, 2016 at 15:31 | comment | added | Divyanshu Shende | Yes. It's supposed to mean L(M) satisfies P. Is the answer okay now? | |
Feb 1, 2016 at 15:31 | history | edited | Divyanshu Shende | CC BY-SA 3.0 |
corrected typo
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Dec 29, 2015 at 5:07 | comment | added | D.W.♦ | It still seems problematic to me. What does "Language of M and satisfies P" mean? Do you mean $L(M)$ satisfies $P$? | |
Dec 28, 2015 at 19:38 | comment | added | Divyanshu Shende | The answer was horribly wrong before. Hopefully, it makes more sense now. | |
Dec 28, 2015 at 19:37 | history | edited | Divyanshu Shende | CC BY-SA 3.0 |
added 198 characters in body
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Dec 17, 2015 at 19:28 | comment | added | David Richerby | What does $\langle L\rangle$ mean? | |
Dec 17, 2015 at 19:27 | history | edited | David Richerby | CC BY-SA 3.0 |
copy-edit, formatting
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Dec 17, 2015 at 19:25 | comment | added | A.Schulz | No. Rice's Theorem says that $\{\langle M \rangle \mid \text{Turing machine }M \text{ accepts a language with property }P\}$ is undecidable. | |
Dec 17, 2015 at 19:21 | review | Late answers | |||
Dec 17, 2015 at 19:28 | |||||
Dec 17, 2015 at 19:04 | review | First posts | |||
Dec 17, 2015 at 22:02 | |||||
Dec 17, 2015 at 19:00 | history | answered | Divyanshu Shende | CC BY-SA 3.0 |