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Feb 26, 2021 at 7:44 comment added Nicolas Raoul @PMende: Good remark, however the question mentions that d is orders of magnitude smaller than the Earth's radius r so it should be acceptable.
Jan 29, 2020 at 17:07 comment added vonbrand @PMende, true. But the distance on the sphere is monotonic on linear distance.
Jan 20, 2020 at 21:58 comment added PMende Just wanted to point out that this answer is simply incorrect. The constrained distance between two points on a sphere (i.e., their distance when you are forced to move along the surface of the sphere) is larger than their straight-line distance you would get from calculating their Euclidean distance. This is easier to see if you consider the simpler case of 2 points on a circle.
Jan 8, 2016 at 18:01 history edited D.W. CC BY-SA 3.0
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Jan 8, 2016 at 16:02 comment added vonbrand @NicolasRaoul, you can e.g. sort the points by one of the coordinates to reduce it to a binary search.
Jan 8, 2016 at 15:15 comment added Nicolas Raoul In 3D! I see, that's doable then. I would still mean calculating for each point of the set, but each calculation would be faster indeed.
Jan 8, 2016 at 13:52 history answered vonbrand CC BY-SA 3.0