Timeline for Algorithm to convert decimal number to binary
Current License: CC BY-SA 3.0
17 events
| when toggle format | what | by | license | comment | |
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| Sep 3 at 0:11 | answer | added | RARE Kpop Manifesto | timeline score: 0 | |
| S Jan 13, 2016 at 11:39 | history | suggested | greybeard | CC BY-SA 3.0 |
exercise in block comment and LaTeX
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| Jan 13, 2016 at 8:52 | review | Suggested edits | |||
| S Jan 13, 2016 at 11:39 | |||||
| Jan 13, 2016 at 8:43 | comment | added | Rui F Ribeiro | I added the Cisco academy algorithm as a curiosity. It is mostly subtractions once you know the powers of two by heart. | |
| Jan 13, 2016 at 8:36 | answer | added | Rui F Ribeiro | timeline score: 1 | |
| Jan 13, 2016 at 8:10 | comment | added | Ravi | @Raphael I have re-typed the algorithm in a readable form. Sorry for the inconvenience. Henceforth I will take care of this. | |
| Jan 13, 2016 at 8:09 | history | edited | Ravi | CC BY-SA 3.0 |
edited for clarity
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| Jan 13, 2016 at 8:03 | vote | accept | Ravi | ||
| Jan 13, 2016 at 8:02 | answer | added | hengxin | timeline score: 5 | |
| Jan 13, 2016 at 8:01 | comment | added | Ravi | @RuiFRibeiro thanks for your reply and assistance. I got the solution. hengxin has commented on this Q. He has mentioned that it should be log. So that is a mistake in the material. "log" is what fits the algorithm perfectly. | |
| Jan 13, 2016 at 7:55 | comment | added | Rui F Ribeiro | Hi Ravi. The algorithm you posted is too complicated. Binary numbers are powers of two, like having only two digits, divisions/multiplications by 2 should be more than enough for a beginner. I got this page for you. interactivepython.org/runestone/static/pythonds/BasicDS/… For dealing with short number, we also have a simpler strategy. | |
| Jan 13, 2016 at 7:53 | comment | added | Ravi | @hengxin Yes your formula is what is fitting the algorithm completely. So that is a mistake in that material. It mentions square root but it is log. Great! I thank you very much for your valuable assistance. | |
| Jan 13, 2016 at 7:46 | comment | added | hengxin | $7 = \text{int} (\log_{2} 236)$. Generally, $p = \text{int} (\log_{B} V)$. | |
| Jan 13, 2016 at 7:41 | comment | added | Raphael | Please spend some effort to re-type the algorithm in a readable form. Relying on external sources (which may change or go away at any point) is no good for SE. Also, have you checked out other base conversion algorithms? This one seems ... needlessly convoluted. | |
| Jan 13, 2016 at 7:40 | history | edited | Raphael |
edited tags
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| Jan 13, 2016 at 7:14 | review | First posts | |||
| Jan 13, 2016 at 10:03 | |||||
| Jan 13, 2016 at 7:10 | history | asked | Ravi | CC BY-SA 3.0 |