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Apr 13, 2017 at 12:48 history edited CommunityBot
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Jan 30, 2016 at 3:31 history edited D.W. CC BY-SA 3.0
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Jan 30, 2016 at 3:07 comment added D.W. @RickyDemer, that aspect is probably of independent interest, so let's take that to a separate question: cs.stackexchange.com/q/52457/755.
Jan 30, 2016 at 2:38 comment added user12859 I don't see how such subtrees can all be found in O(log(n)) time. ​ ​
Jan 29, 2016 at 1:36 comment added D.W. @RickyDemer, I've updated my answer to address that point. You're right: we might potentially need to delete an entire range of consecutive points in the frontier. Fortunately, that too can be done in $O(\lg n)$ time, using properties of balanced binary trees. Do you agree? If you agree, shall we clean up our comments?
Jan 29, 2016 at 1:35 history edited D.W. CC BY-SA 3.0
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Jan 25, 2016 at 6:59 vote accept JnBrymn
Jan 25, 2016 at 5:13 comment added user12859 In two dimensions, how are now-strictly-dominated elements removed in O(log(n)) time? ​ ​
Jan 25, 2016 at 3:19 history edited D.W. CC BY-SA 3.0
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Jan 24, 2016 at 23:06 comment added user12859 See "remove all other elements because this dominates them in both dimensions". ​ (There can easily be a linear number elements to be removed, so if you have to do that one element at a time, then updates can take worst-case O(n) time.) ​ ​ ​ ​
Jan 24, 2016 at 20:50 comment added D.W. @JnBrymn, see my updated answer: I added a paragraph to the end to address the situation in higher dimensions.
Jan 24, 2016 at 20:50 history edited D.W. CC BY-SA 3.0
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Jan 24, 2016 at 16:42 comment added JnBrymn This is a good answer. Though it brings to my attention that I implied a constraint with my example that I didn't intend to. In my example I'm using 2-tuples, but I would need an algorithm that handles N-tuples.
Jan 24, 2016 at 14:36 comment added user12859 Do balanced binary trees allow ​ O($\hspace{.02 in}$log(n))-time ​ deletions of ranges? ​ ​ ​ ​
Jan 24, 2016 at 13:44 history answered D.W. CC BY-SA 3.0