Timeline for Regular language with pumping lemma
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Sep 23, 2016 at 18:13 | history | edited | Hendrik Jan | CC BY-SA 3.0 |
empty language gives me an headache.
|
Sep 23, 2016 at 18:01 | comment | added | Hendrik Jan | @JanDvorak Exactly. When replacing in the automaton for the concatenation all transitions from one alphabet by $\epsilon$ transitions one obtains a finite state automaton for the other half. If needed these $\epsilon$ can be removed by standard techniques. (Just removing the transitions leaves us with the task of deciding where to begin/end.) | |
Sep 23, 2016 at 16:51 | comment | added | John Dvorak | To prove the theorem, consider a FSM recognizing L1L2 and remove from it the transition states corresponding to one of L1 or L2? | |
Sep 23, 2016 at 13:00 | history | answered | Hendrik Jan | CC BY-SA 3.0 |