Timeline for Why does this Pumping Lemma example show irregularity?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 10, 2020 at 19:23 | comment | added | gnasher729 | If the length of s is > p, then you can't pick z = eps because that would make the length of xy > p. xy must be completely contained within the first p characters, so z must be long enough for that. | |
| Feb 10, 2020 at 19:20 | answer | added | gnasher729 | timeline score: 1 | |
| Feb 10, 2020 at 16:23 | comment | added | vonbrand | You don't get to choose your string's division, i.e., you can't pick $z = \epsilon$. | |
| Sep 29, 2016 at 21:39 | history | tweeted | twitter.com/StackCompSci/status/781609490206654464 | ||
| Sep 29, 2016 at 17:25 | answer | added | Anjo | timeline score: 0 | |
| Sep 29, 2016 at 17:03 | answer | added | Hans Hüttel | timeline score: 4 | |
| Sep 29, 2016 at 9:41 | answer | added | Shubham Singh rawat | timeline score: 3 | |
| Sep 29, 2016 at 8:16 | history | edited | Raphael |
edited tags
|
|
| Sep 28, 2016 at 23:41 | review | First posts | |||
| Sep 30, 2016 at 13:23 | |||||
| Sep 28, 2016 at 23:37 | answer | added | David Richerby | timeline score: 4 | |
| Sep 28, 2016 at 23:25 | history | asked | Jordan Andy | CC BY-SA 3.0 |