Skip to main content
5 events
when toggle format what by license comment
Mar 19, 2014 at 4:20 comment added Niklas B. Oh I see. I thought OP was saying $n = |V| = |E|$ or something :) Pardon my lack of reading comprehension
Mar 19, 2014 at 4:09 comment added Falk Hüffner The Hungarian algorithm solves the problem in O(k^3) for a kxk matrix. Here, we have k = |V| and n := |E| = O(k^2). I guess this could be a bit confusing since in this question n means something different than normally in graph problems.
Mar 18, 2014 at 22:08 comment added Niklas B. What algorithm would one use to solve this in $O(n^{1.5})$?
Nov 4, 2012 at 17:40 review First posts
Nov 7, 2012 at 10:48
Nov 4, 2012 at 17:24 history answered Falk Hüffner CC BY-SA 3.0