Timeline for Confused between turing-completeness and universal approximation - are they related?
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8 events
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Apr 17, 2019 at 6:33 | comment | added | D.W.♦ | @samlaf, could be -- that exceeds my knowledge. I don't know enough about the BSS model to have an informed opinion about your question. Sorry! | |
Apr 17, 2019 at 3:39 | comment | added | samlaf | Would the BSS machine (from what I understand, real-valued TM) be a way to link these concepts? It seems that being BSS-complete implies both Turing-complete and Universal Approximator. | |
Jan 17, 2017 at 0:41 | comment | added | D.W.♦ | @Redcoat, I don't agree, because Turing-complete talks about functions on booleans, while universal-approximator talks about functions on real numbers. At this point I suspect maybe what would be most useful would be to familiarize yourself with the precise, mathematical definition of each of those two concepts. | |
Jan 16, 2017 at 20:08 | comment | added | Spacey | Thanks DW! It is getting clearer - however in my mind, there does seem to be a link: For example, it seems to me then, that one cannot have a turing-machine that is NOT a universal approximator simultaneously, right? In that sense, being turing-complete, would also mean that you are a universal approximator. Would you agree with this? | |
Jan 16, 2017 at 20:03 | comment | added | D.W.♦ | @Redcoat, good questions! I added another paragraph to my answer; see revised answer (last paragraph). | |
Jan 16, 2017 at 20:02 | history | edited | D.W.♦ | CC BY-SA 3.0 |
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Jan 16, 2017 at 19:58 | comment | added | Spacey | Hmm, thanks for the answer, although I am still confused somewhat: Let me phrase a different way: How is it that a non-turing-complete machine can also be a universal approximator? Does that mean that universal-approximation is a "weaker" criteria of machines that "turing-completeness"? | |
Jan 16, 2017 at 19:06 | history | answered | D.W.♦ | CC BY-SA 3.0 |