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Dec 30, 2017 at 22:31 history edited Ross Millikan CC BY-SA 3.0
correct
Dec 4, 2017 at 3:15 comment added Ross Millikan @Yakk: I think this answers the question of why there is a problem. The answer is stable, if perhaps not accurate. Yes, to make a good algorithm one would need to check the magnitude of $\frac xa$ and decide if more terms were needed.
Feb 7, 2017 at 14:39 comment added Yakk Stopping at the first term may also lead to some issues; you should at least generate a numerically stable error term, so you'd be aware if you have tiny error or not.
Feb 7, 2017 at 2:25 review First posts
Feb 7, 2017 at 6:48
Feb 7, 2017 at 2:24 history answered Ross Millikan CC BY-SA 3.0