Timeline for Why is computation of this function numerically unstable?
Current License: CC BY-SA 3.0
5 events
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Dec 30, 2017 at 22:31 | history | edited | Ross Millikan | CC BY-SA 3.0 |
correct
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Dec 4, 2017 at 3:15 | comment | added | Ross Millikan | @Yakk: I think this answers the question of why there is a problem. The answer is stable, if perhaps not accurate. Yes, to make a good algorithm one would need to check the magnitude of $\frac xa$ and decide if more terms were needed. | |
Feb 7, 2017 at 14:39 | comment | added | Yakk | Stopping at the first term may also lead to some issues; you should at least generate a numerically stable error term, so you'd be aware if you have tiny error or not. | |
Feb 7, 2017 at 2:25 | review | First posts | |||
Feb 7, 2017 at 6:48 | |||||
Feb 7, 2017 at 2:24 | history | answered | Ross Millikan | CC BY-SA 3.0 |