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Feb 28, 2018 at 10:50 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 28, 2018 at 22:41 answer added Discrete lizard timeline score: 2
Mar 27, 2017 at 6:49 comment added user35837 this is due the properties of chordal completion for original graph.
Mar 24, 2017 at 20:15 comment added user53923 Ah no I was trying to say that if you take a tree decomposition of the chordal completion, you clearly have a bag of size k , but it could be less obvious for the original graph. (And yes I see I have missed that annoying -1 again... You are right)
Mar 24, 2017 at 16:53 comment added user35837 I think you are talking about this $tw(G) ≥ ω(G) − 1$ , but see in the claim 1 I am not saying largest clique in $G$, I am saying largest clique in chordal completion of $G$.
Mar 24, 2017 at 16:37 history edited user35837 CC BY-SA 3.0
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Mar 24, 2017 at 16:30 history edited user35837 CC BY-SA 3.0
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Mar 24, 2017 at 16:20 comment added user35837 your question is valid but I think it follows from the definition of tree - width ( by chordal i.e. definition 1) so it is true for original graph or am I missing something ? and for second thing you mean to say $k -1$ or at least $k$ ( see the last paragraph en.wikipedia.org/wiki/Chordal_graph)
Mar 24, 2017 at 15:40 comment added user53923 About the proof of claim 1: It is indeed clear that the chordal completion has treewidth k, from your proof it is not obvious that this is true for the original graph. Also, you may want to rephrase your claims. Claim 1: If size of largest clique in a chordal decomposition of graph is say k then by tree decomposition we will get tree width at least k
Mar 23, 2017 at 8:53 history tweeted twitter.com/StackCompSci/status/844834496658661377
Mar 22, 2017 at 12:29 history edited user35837
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Mar 22, 2017 at 10:51 history asked user35837 CC BY-SA 3.0