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May 24, 2020 at 0:54 history edited Curious_Dim CC BY-SA 4.0
corrected inequality from w(T'-e)<w(T) to w(T'-e)<w(T-e)
May 24, 2020 at 0:49 comment added Curious_Dim @sas I am using that inequality but not explicitly. If you notice I begin by saying that by the same sequence.... And I mean by the same sequence of operations I did in the previous case in which I used the inequality. What you suppose for G, that w(T')< w(T-e) +w'(e) is arbitrary. But indeed I made I mistake in second case I will correct now. I should begin with w(T'-e)<w(T-e) in second case instead of w(T'-e)<w(T).
Apr 23, 2020 at 20:58 comment added sas Smth wrong in the second case. You are not actually using $w'(e)<w(e)$. I suppose, in $G$ $w(T')<w(T-e) + w'(e)< w(T-e) + w(e) = w(T)$
Jan 27, 2018 at 6:31 history edited Curious_Dim CC BY-SA 3.0
had a mistake in case $e \notin T'$ which I fixed
Jan 27, 2018 at 6:10 history answered Curious_Dim CC BY-SA 3.0