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Mar 24 at 9:55 answer added NinjaDarth timeline score: 0
Apr 22, 2018 at 11:02 answer added baronbrixius timeline score: 1
Apr 20, 2018 at 15:32 comment added baronbrixius The first two are allowed, the third one is not.
Apr 20, 2018 at 10:22 comment added chi What is a "combinator in terms of a $B$ only", precisely? I.e. are $BBBabcdef, B(BB)abcdef, Ba(Bbcd)(Bef)$ allowed as "only in terms of $B$"? (Note that none of these is a solution, I just want to understand the rules of the game.) Which ones could be allowed?
Apr 20, 2018 at 6:48 review First posts
Apr 20, 2018 at 7:17
Apr 20, 2018 at 6:44 history asked baronbrixius CC BY-SA 3.0