2
$\begingroup$

Having large matrices, $W$ (the unknown) and $M$ (known), is it possible to solve for $W$ in this equation $$W \cdot W^{T} = M,$$ where $M$ can have negative entries.

$\endgroup$

1 Answer 1

3
$\begingroup$

You might be looking for the Cholesky decomposition. The referenced article also contains an example for $M$ having negative entries. Note the constraints on $M$ for this decomposition to exist.

$\endgroup$
1
  • $\begingroup$ Even in Cholesky decomposition, the equation is solved by assuming $W$ to be made up of rows containing $a_{11},a_{12}\ldots a_{1n}$ and then equating the corresponding entries of $WW^T$with $M$. Isn't this the brute force algorithm? $\endgroup$
    – nitishch
    Commented Mar 5, 2014 at 15:07

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.