3
$\begingroup$

In linear time logic, is $\mathbf{GF}p$ equivalent to $ \mathbf{G}p$ ?

$\mathbf{GF}p$ means that it is always the case that p is true eventually.

Let $\mathbf{G} p$ be defined as: $\forall j \ge0,\ p$ holds in the suffix $q_j, q_{j+1}, q_{j+2},\ldots$

and since: formula $φ$ holds for state machine $M$ if $φ$ holds for all possible traces of $M$

Isn't $\mathbf{G}$ in $\mathbf{GF}p$ redundant then?

$\endgroup$

1 Answer 1

5
$\begingroup$

No, not equivalent and not redundant.

Consider $p$ being true if and only if $j$ is even. $\mathbf{G}p$ is not true (obviously, since $p$ is false in every odd state), but $\mathbf{GF}p$ is always true.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.