# What does a proof that Co-NP =P entail for the NP versus Co-NP question

What I wonder is what exactly would it entail. Would it,for instance imply that P=NP or would there be different consequences,I haven't found any assorted consequences so far in my research. Thank You, Akash

$$\text{P}=\text{co-NP}$$ implies that $$\text{co-P}=\text{co-(co-NP)}=\text{NP}$$. But $$\text{co-P}=\text{P}$$: you can just swap the accept and reject states of a deterministic Turing machine to complement the language that it decides.