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The Boolean expression I find on the internet for the sum bit of a full adder is A xor B xor Cin. Does't this expression exclude the A=1,B=1,Cin=1 situation? When that happens, the sum bit is also 1, isn't it?

Thank you very much.

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  • $\begingroup$ Like additions, A xor B xor C = (A xor B) xor C = A xor (B xor C) $\endgroup$ – TEMLIB May 7 '20 at 23:02
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1 xor 1 xor 1 = 1, so this is correct in that case as well.

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