Problem Set Solutions/Interrupts & Exceptions/Problem 1

Using Tomasulo’s algorithm, for each instruction in the listed sequence determine when (in which cycle, counting from the start) it issues, begins execution, and writes its result to the CDB. Assume that the result of an instruction can be written in the last cycle of its execution, and that a dependent instruction can (if selected) begin its execution in the cycle after that. The execution time of all instructions is two cycles, except for multiplication (which takes 4 cycles) and division (which takes 8 cycles). The processor has one multiply/divide unit and one add/subtract unit. The multiply/divide unit has two reservation stations and the add/subtract unit has four reservation stations. None of the execution units is pipelined – each can only be executing one instruction at a time. If a conflict for the use of an execution unit occurs when selecting which instruction should start to execute, the older instruction (the one that appears earlier in program order) has priority. If a conflict for use of the CBD occurs, the result of the add/subtract unit has priority over the result of the multiply/divide unit. Assume that at start all instructions are already in the instruction queue, but none has yet been issued to any reservation stations. The processor can issue only one instruction per cycle, and there is only one CDB for writing results.

Can someone explain why for Instruction 1 the write happens in cycle 5 ? It is given in the question that MUL takes 4 cycles to execute. So write for I1 should have happened in cycle 6 ?

• I don't think this is answerable unless you specify on what sort of processor/assembly language this is. Please edit your question to clarify so that the meaning of all commands and registers is clear. Apr 22, 2019 at 16:33
• updated the question Apr 22, 2019 at 18:22
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– D.W.
Apr 24, 2019 at 19:27