# which rule can conduct this formula $\log n = O(n^{0.000001})$? [duplicate]

i am learning this post about Big O, which gives this formula

$$\log n = O(n^{0.000001})$$

why is that?

## marked as duplicate by David Richerby, Juho, Discrete lizard♦May 16 at 9:44

• @Bulat Not necessarily. Even somebody who knows the definition might not know why $\log n = O(n^{0.000001})$. – David Richerby May 16 at 8:54