# why is $O(n^2)$ equal to $n^{1.5}$?

I am learning this MIT course, which gives this formula

$$O(n^2) = n^{1.5}$$

is there a table to calculate this? like $$O(n^{1.5})$$, $$O(n^{5})$$ ?

what x takes would have O(x) give $$c \cdot n$$ where c is a constant,

• can you citate us teh definition of O? this will immediately give yiou an answer – Bulat May 19 at 8:40

The formula is wrong. The notation $$f = O(g)$$ is asymmetric, and has the meaning $$f \in O(g)$$. For more, check our reference question on Landau notation. Other relevant reference questions are this one and this one.