per this post

$t = x^2$ means the problem is solvable in "Polynomial" time.

per this post

in the form

$$a_{n}x^{n}+a_{n-1}x^{n-1}+\dotsb +a_{2}x^{2}+a_{1}x+a_{0} { > \boldsymbol{=0}}$$

plug in $n=100000000000$ with $a_n=1$ and $a_k=0$ for all $k \neq n$

then we see that $x^{100000000000}$ is a polynomial

it doesn't matter if its 2, 3, or a billion, as long as the n is a finite number

in this context, does $t = x^{100000000000}$ still mean the problem is solvable in "Polynomial" time?

  • 2
    $\begingroup$ I suggest you read up on what a polynomial is. $\endgroup$ – dkaeae Jun 7 '19 at 7:00
  • $\begingroup$ I'm voting to close this question as it is not about CS but rather about basic math terminology. $\endgroup$ – dkaeae Jun 7 '19 at 7:01

Yes, $x^{100000000000}$ is a polynomial. Your first quote gives an example; your second is the definition.

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