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I am just starting out learning code.

The output of the following code is OOOXOXOO, but I don't see how X can be printed twice. How does a=2 more than once?

a = 1
while a < 3:
    b = 1
    while b < 3:
        if a == 2:
            print ("X"),
        print ("O"),
        b = b + 1
    print ("O"),
    a = a + 1
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closed as off-topic by dkaeae, Evil, xskxzr, Discrete lizard Jul 3 at 12:10

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question does not appear to be about computer science, within the scope defined in the help center." – dkaeae, Evil, xskxzr, Discrete lizard
If this question can be reworded to fit the rules in the help center, please edit the question.

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Think carefully about the flow.

Your innermost While loop runs through b = 1, 2, each time it hits.

It does this for EACH value of a in the outermost loop.

So when a == 2, we progress inward and run through that loop twice. a == 2 both times.

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  • $\begingroup$ Okay that makes sense, thank you so much. I'm running through some course material on my own, so I don't have a professor to ask about this. I was confused about which order the loops would run in. Thanks again for taking the time to help me with this! $\endgroup$ – BenG Jul 1 at 15:38

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